The velocity and acceleration vectors of a particle undergoing circular motion are v = 4 i ^ m / s and a = 4 i ^ + 2 j ^ m / s 2 respectively at an instant of time. The radius (in m) of the circle is :

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Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionKinematicsMedium3 minQB

PhysicsMediuminteger

The velocity and acceleration vectors of a particle undergoing circular motion are $v = 4 \hat{i} m / s$ and $a = 4 \hat{i} + 2 \hat{j} m / s^{2}$ respectively at an instant of time. The radius (in m) of the circle is :

Answer:

Solution:

Only the acceleration component perpendicular to v changes the direction: $a_{⊥} = 2 m / s^{2}$ .

$a_{⊥} = \frac{v ^{2}}{R} \Rightarrow R = \frac{16}{2} = 8 m$

Answer: 8

Stream:JEESubject:PhysicsTopic:Circular MotionSubtopic:Kinematics

⏱ 3mℹ️ Source: QB

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