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Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionDynamicsMedium2 minPYQ_2021

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A particle of mass $m$ is suspended from a ceiling through a string of length $L$ . The particle moves in a horizontal circle of radius $r$ such that $r = \frac{L}{\sqrt{2}}$ . The speed of particle will be :

Question diagram: A particle of mass m is suspended from a ceiling through a s

Options:

Answer:

A

Solution:

$\sin θ = \frac{1}{\sqrt{2}}$

$θ = 45 °$

$\tan θ = \frac{\frac{m v^{2}}{r}}{m g} = \frac{v^{2}}{r g} = 1$

$v^{2} = rg$

$v = \sqrt{r g}$

Stream:JEESubject:PhysicsTopic:Circular MotionSubtopic:Dynamics

⏱ 2mℹ️ Source: PYQ_2021

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