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PhysicsSHMOscillations and SHMMedium2 min

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A particle starts from its equilibrium position at $t = 0$ with period $T$ . Find $K E : PE$ at $t = T /6$ .

Answer:

Solution:

At $T /6$ the phase is $6 0^{\circ}$ : $x = \frac{3}{2} A$ , $PE \propto \frac{3}{4}$ , $K E \propto \frac{1}{4}$ . Ratio $1 : 3$ .

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

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