1 kg of a gas does 20 kJ of work and receives 16 kJ of heat when it is expanded between two states. A second kind of expansion can be found between the same initial and final states which requires a h

Question

1 kg of a gas does 20 kJ of work and receives 16 kJ of heat when it is expanded between two states. A second kind of expansion can be found between the same initial and final states which requires a heat input of 9 kJ. The work done by the gas in the second expansion is

Options:

Answer:

D

Solution:

$Δ U$ is path-independent: $Δ U = Q_{1} - W_{1} = 16 - 20 = - 4$ kJ.

Second path: $W_{2} = Q_{2} - Δ U = 9 - (- 4) = 13$ kJ.

TestHub · Accepted Answer

Δ U is path-independent: Δ U = Q 1 ​ − W 1 ​ = 16 − 20 = − 4 kJ. Second path: W 2 ​ = Q 2 ​ − Δ U = 9 − ( − 4 ) = 13 kJ.

Physics - Heat & Thermo Question with Solution | TestHub

Options:

Doubts & Discussion