The percentage change in volume of a brass sphere of radius 8 cm on going from 0 ∘ C to 10 0 ∘ C is nearly: α b r a ss = 19 × 1 0 − 6 ∘ C − 1 .

V Δ V ≈ 3 α Δ T V Δ V ≈ 3 × 19 × 1 0 − 6 × 100 V Δ V ≈ 0.0057 Percentage increase = 0.57%

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermal ExpansionEasy2 minQB

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The percentage change in volume of a brass sphere of radius $8 cm$ on going from $0^{\circ} C$ to $10 0^{\circ} C$ is nearly: $α_{b r a ss} = 19 \times 1 0^{- 6}^{\circ} C^{- 1}$ .

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Answer:

Solution:

$\frac{Δ V}{V} \approx 3 α Δ T$
$\frac{Δ V}{V} \approx 3 \times 19 \times 1 0^{- 6} \times 100$
$\frac{Δ V}{V} \approx 0.0057$
$Percentage increase = 0.57%$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

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