Physics - SHM Question with Solution | TestHub

Speed is larger near the mean position, so time from 0 to A/2 is less than from A/2 to A. (A) is false.

Average velocity over one period = displacement/T = 0, not $4A/T$. (B) is false.

Over one period $\Delta KE=0$, so net work done is 0. (C) is true.

Kinetic energy is maximum at the mean position. (D) is true.

Answer: C,D