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PhysicsHeat & ThermoKTGMedium2 minQB

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An ideal gas undergoes two processes 1 and 2 as shown. If $v_{1}$ and $v_{2}$ are the volumes in processes 1 and 2, then

Answer:

Solution:

For a P-T graph, $P = \frac{n R}{V} T$ : slope $\propto \frac{1}{V}$ . Slope of $1 >$ slope of $2 \Rightarrow V_{1} < V_{2}$ .

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: QB

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