Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoDifferent processesEasy2 minPYQ_2014

PhysicsEasysingle choice

During an adiabatic compression, $830 J$ of work is done on 2 moles of a diatomic ideal gas to reduce its volume by $50%$ . The change in its temperature is nearly: $(R = 8.3 JK^{- 1} mol^{- 1})$

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Answer:

Solution:

Given : work done, $W = 830 J$ No. of moles of gas, $μ = 2$ For diatomic gas $γ = 1.4$ Work done during an adiabatic change $W = \frac{μ R ( T _{1} - T _{2} )}{γ - 1} \Rightarrow 830 = \frac{2 \times 8.3 ( Δ T )}{1.4 - 1} = \frac{2 \times 8.3 ( Δ T )}{0.4} \Rightarrow Δ T = \frac{830 \times 0.4}{2 \times 8.3} = 20 K$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Different processes

⏱ 2mℹ️ Source: PYQ_2014

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