A hall has a volume of 500 m 3 . Find the mass of air in it at 0 ∘ C and 1 atm (kg, nearest integer). Molar mass of air 0.029 kg/mol.

m = RT P V M = 8.314 × 273 1.013 × 1 0 5 × 500 × 0.029 = 647 kg. If the temperature then rises to 3 0 ∘ C the mass leaving is 64 kg.

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PhysicsHeat & ThermoKinetic Theory of Gases and Gas LawsMedium2 minQB

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A hall has a volume of 500 $m^{3}$ . Find the mass of air in it at $0^{\circ}$ C and 1 atm (kg, nearest integer). Molar mass of air 0.029 kg/mol.

Answer:

647.00

Solution:

$m = \frac{P V M}{RT} = \frac{1.013 \times 1 0 ^{5} \times 500 \times 0.029}{8.314 \times 273} = 647$

kg. If the temperature then rises to $3 0^{\circ}$ C the mass leaving is

64 kg.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Kinetic Theory of Gases and Gas Laws

⏱ 2mℹ️ Source: QB

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