A liquid of cubical expansion coefficient γ has density ρ at 0 ∘ C . Its density change on heating to T ∘ C is:

ρ ′ = ( 1 + γ T ) ρ . Δ ρ = ρ ′ − ρ = − ( 1 + γ T ρ γ T .

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A liquid of cubical expansion coefficient $γ$ has density $ρ$ at $0^{\circ} C$ . Its density change on heating to $T^{\circ} C$ is:

Answer:

Solution:

$ρ^{'} = \frac{ρ}{( 1 + γ T )}$ .

$Δ ρ = ρ^{'} - ρ = - \frac{ρ γ T}{( 1 + γ T} .$

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

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