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PhysicsNLMSimple Application of NLMMedium2 minQB
PhysicsMediuminteger

Two blocks of same mass starts their motion as shown. After t time their separation becomes minimum. If the value of k is

Answer:
2
Solution:

Released from rest, each block has acceleration a = g(1 - sin(theta))/2 (hanging block down, incline block up the plane). Let u and w be the string lengths from the pulley to the incline block and to the hanging block. The straight-line separation obeys d^2 = u^2 + w^2 - 2uw sin(theta), which is minimum when u = w. With u = h/sin(theta) - (1/2) a t^2 and w = (1/2) a t^2, u = w gives a t^2 = h/sin(theta), so t = sqrt(2h / (g sin(theta) (1 - sin(theta)))). Hence k = 2.

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Simple Application of NLM
⏱ 2mℹ️ Source: QB

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