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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Work kinetic energy theoremMedium2 minQB

PhysicsMediumsingle choice

The system is released from rest when spring is at its natural length. Spring constant is 100 N/m and mass of each block is 10 kg. The velocity 'v' of block A as a function of position x is given as $v^{2} = ax - bx^{2}$ . The value of a/b is equal to.

Options:

Answer:

Solution:

The two blocks move together while B descends x:

$\frac{1}{2} (2 m) v^{2} = m gx - \frac{1}{2} k x^{2} \Rightarrow v^{2} = gx - \frac{k}{2 m} x^{2}$

$\frac{a}{b} = \frac{g}{k /2 m} = \frac{2 m g}{k} = \frac{2 \times 10 \times 10}{100} = 2$

Ans. (B)

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Work kinetic energy theorem

⏱ 2mℹ️ Source: QB

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