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PhysicsW.E.P.Conservative force & potential energyEasy2 minPYQ_2020

PhysicsEasynumerical

The potential energy of a particle under a conservative force is given by $U (x) = (x^{2} - 3 x) J$ . The equilibrium position of the particle is at $x m$ . The value of $10 x$ will be

Answer:

15.00

Solution:

$U (x) = (x^{2} - 3 x) J$
For a conservative field, Force, $F = - \frac{d U}{d x}$

$∴ F = - \frac{d}{d x} (x^{2} - 3 x) = - (2 x - 3) = - 2 x + 3$

At equilibrium position, $F = 0$

$- 2 x + 3 = 0 \Rightarrow x = \frac{3}{2} m = 1 \cdot 5 m$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Conservative force & potential energy

⏱ 2mℹ️ Source: PYQ_2020

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