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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Conservative force & potential energyMedium2 minQB

PhysicsMediummultiple choice

In figure shown, the spring constant is K. The mass of the upper block is m and that of the lower block is 3m. The upper block is depressed down from its equilibrium position by a distance $δ$ and released at $t = 0$ .

Options:(select one or more)

Answer:

A, B

Solution:

Equilibrium compression is $m g / K$ ; the upper block executes SHM of amplitude $δ$ about it. Maximum spring extension at the top: $δ - m g / K$ .

The lower block loses contact when the spring pulls it up with 3mg: $K (δ - m g / K) = 3 m g \Rightarrow δ = 4 m g / K$ - (A) correct, (C) wrong.

Minimum normal = mg: $3 m g - K (δ - m g / K) = m g \Rightarrow δ = 3 m g / K$ - (B) correct, (D) wrong.

Ans. (A,B)

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Conservative force & potential energy

⏱ 2mℹ️ Source: QB

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