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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermal ExpansionMedium2 minQB

PhysicsMediumsingle choice

The temperature T on a thermometric scale is defined in terms of a property K by the relation $T = a ln K + b$ where a and b are constants. The values of K is found to be 2 and 8 at the ice point and steam point respectively. Temperature corresponding to $K = 4$ is

Options:

Answer:

Solution:

Subtract the ice-point relation from the steam-point relation.
$100 = a ln (\frac{8}{2}) = a ln 4$
$T = a ln (\frac{4}{2}) = a ln 2$
$T = 50^{\circ} C$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

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