A particle of mass 20 g moves in a field with potential energy per unit mass U = 2 × 1 0 4 x 2 erg/g. Its total energy is 1 × 1 0 7 erg. Find the relation between x and t ( ϕ = constant).

2 1 ω 2 = 2 × 1 0 4 gives ω = 200 rad/s. E = 2 1 ( 20 ) 20 0 2 A 2 = 1 0 7 gives A 2 = 25 cm², so A = 5 cm.

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PhysicsSHMOscillations and SHMMedium2 min

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A particle of mass 20 g moves in a field with potential energy per unit mass $U = 2 \times 1 0^{4} x^{2}$ erg/g. Its total energy is $1 \times 1 0^{7}$ erg. Find the relation between $x$ and $t$ ( $ϕ$ = constant).

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Answer:

Solution:

$\frac{1}{2} ω^{2} = 2 \times 1 0^{4}$ gives $ω = 200$ rad/s. $E = \frac{1}{2} (20) 20 0^{2} A^{2} = 1 0^{7}$ gives $A^{2} = 25$ cm², so $A = 5$ cm.

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

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