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Physics - Fluid Question with Solution | TestHub

PhysicsFluidArchimedes principleMedium2 minQB

PhysicsMediumsingle choice

A hemispherical portion of radius R is removed from the bottom of a cylinder of radius R. The volume of the remaining cylinder is V and its mass is M. It is suspended by a string in a liquid of density $ρ$ where it stays vertical. The upper surface of the cylinder is at a depth h below the liquid surface. The force on the bottom of the cylinder by the liquid is (Neglect atmospheric pressure)

Options:

Answer:

Solution:

Upward force on bottom $-$ downward force on top = buoyancy.

$F_{bottom} - ρ g h π R^{2} = ρ g V$

$F_{bottom} = ρ g (V + π R^{2} h)$

. Answer D.

Stream:JEESubject:PhysicsTopic:FluidSubtopic:Archimedes principle

⏱ 2mℹ️ Source: QB

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