A boy of mass 10 kg is standing on a 4 kg block as shown. The whole system is on smooth level ground. The boy jumps to the right with a velocity of 7 m/s relative to the 4 kg block. Find the maximum velocity 'v' of 1 kg block (in m/sec) in the subsequent motion.

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Jump: momentum gives 10 v b ​ + 4 v b l ​ = 0 with v b ​ − v b l ​ = 7 , so the 4 kg block moves at 5 m/s toward the spring. Maximum velocity of the 1 kg block occurs when the spring returns to natural length (elastic-like transfer): v 1 ​ = 4 + 1 2 × 4 ​ × 5 = 8 m/s Ans. 8

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