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PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesMedium2 minQB

PhysicsMediumsingle choice

A gas obeys $P V^{3} = constant$ in addition to $P V = RT$ . If on heating its temperature is doubled, the volume:

Answer:

Solution:

Dividing, $T V^{2} = constant$ . Doubling $T$ gives $V_{2} = \frac{V _{1}}{2}$ , a fall of $1 - 0.707 = 0.293$ , or 29.3%. A.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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