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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoHeat TransferMedium2 min

PhysicsMediumnumerical

A source of radiation gives an intensity 5 W $m^{- 2}$ at a distance of 3 m. Its absolute temperature is increased by 50% (to 1.5 times). Find the intensity at a distance of 6 m in W $m^{- 2}$ (two decimals).

Answer:

6.33

Solution:

Intensity $\propto T^{4}$ and $\propto \frac{1}{r ^{2}}$ . New value = $5 \times 1.5^{4} \times (\frac{3}{6})^{2} = 5 \times 5.0625 \times 0.25 = 6.33$ W $m^{- 2}$ .

Subject:PhysicsTopic:Heat & ThermoSubtopic:Heat Transfer

⏱ 2m

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