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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKTGMedium2 minQB

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N moles is diatomic gas present in a vessel has molar heat capacity at constant volume equal to 5R/2. Now if 20\% molecules dissociate into monoatoms then what will be the new value of molar heat capacity at constant volume?

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Answer:

Solution:

0.8N moles remain diatomic $(C_{V} = \frac{5}{2} R)$ and 0.2N molecules become 0.4N moles of monoatoms $(C_{V} = \frac{3}{2} R)$ . New $C_{V} = \frac{0.8 \times \frac{5}{2} + 0.4 \times \frac{3}{2}}{1.2} R = \frac{2 + 0.6}{1.2} R = \frac{2.6}{1.2} R = \frac{13 R}{6}$ .

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: QB

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