0.55 g of dry ice is sealed in a 10 c m 3 tube and all of it vaporises at 2 7 ∘ C. Find the pressure in MPa (two decimals).

n = 44 0.55 = 0.0125 mol. P = V n RT = 1 0 − 5 0.0125 × 8.314 × 300 = 3.12 MPa.

Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKinetic Theory of Gases and Gas LawsMedium2 minQB

PhysicsMediumnumerical

0.55 g of dry ice is sealed in a 10 $c m^{3}$ tube and all of it vaporises at $2 7^{\circ}$ C. Find the pressure in MPa (two decimals).

Answer:

3.12

Solution:

$n = \frac{0.55}{44} = 0.0125$ mol. $P = \frac{n RT}{V} = \frac{0.0125 \times 8.314 \times 300}{1 0 ^{- 5}} = 3.12$ MPa.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Kinetic Theory of Gases and Gas Laws

⏱ 2mℹ️ Source: QB

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