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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamics Laws & Specific Heats of GasesHard2 minQB

PhysicsHardnumerical

Three moles of helium at 3 atm and $2 7^{\circ}$ C are adiabatically compressed to one-fourth of their volume. Find the work done on the gas in kJ (one decimal, $R = 8.314$ J $m o l^{- 1}$ $K^{- 1}$ ).

Answer:

17.10

Solution:

$T_{2} = 300 \times 4^{\frac{2}{3}} = 756.0$ K. $W_{o n} = n C_{v} Δ T = 3 \times 1.5 \times 8.314 \times 456.0 = 17.1$ kJ.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics Laws & Specific Heats of Gases

⏱ 2mℹ️ Source: QB

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