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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoConductionMedium2 min

PhysicsMediumsingle choice

Two different rods A and B are kept as shown in figure. The variation of temperature of different cross sections is plotted in a graph shown in figure. The ratio of thermal conductivities of A and B is

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Solution:

$∵ (\frac{Δ Q}{Δ t})_{A} = (\frac{Δ Q}{Δ t})_{B} ∴ \frac{K _{A} A ( 100 - 70 )}{30} = \frac{K _{B} A ( 70 - 35 )}{70} \Rightarrow K_{A} = \frac{K _{B}}{2} \Rightarrow \frac{K _{A}}{K _{B}} = \frac{1}{2}$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Conduction

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