A body cools from 6 0 ∘ C to 5 0 ∘ C in 10 minutes. If the temperature of the room is 2 5 ∘ C and Newton's law of cooling holds good, the temperature of the body at the end of the next 10 minutes will be:

First interval: 10 10 = k ( 55 − 25 ) , so k = 30 1 . Second: 10 50 − T = 30 1 ( 2 50 + T − 25 ) = 60 T . So 50 − T = 6 T and T = 42.86 ∘ C. C.

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoHeat TransferMedium2 min

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A body cools from $6 0^{\circ}$ C to $5 0^{\circ}$ C in 10 minutes. If the temperature of the room is $2 5^{\circ}$ C and Newton's law of cooling holds good, the temperature of the body at the end of the next 10 minutes will be:

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Answer:

Solution:

First interval: $\frac{10}{10} = k (55 - 25)$ , so $k = \frac{1}{30}$ . Second: $\frac{50 - T}{10} = \frac{1}{30} (\frac{50 + T}{2} - 25) = \frac{T}{60}$ . So $50 - T = \frac{T}{6}$ and $T = 42.86^{\circ}$ C. C.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Heat Transfer

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