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A 100 Newton weight is suspended in a corner of a room by two cords A and B as shown in the figure below. The tension in the horizontal cord A is

Answer:

Solution:

$100$

$T_{B} cos 6 0^{\circ} = 100 \Rightarrow T_{B} = 200 N T_{B} sin 6 0^{\circ} = T_{A} T_{A} = 1003 N]$

Stream:JEESubject:PhysicsTopic:NLM

⏱ 2mℹ️ Source: QB

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