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Physics - Fluid Question with Solution | TestHub

PhysicsFluidSurface TensionMedium3 minQB

PhysicsMediumsingle choice

Two soap bubbles of radii $r_{1}$ and $r_{2}$ equal to 4 cm and 5 cm are touching each other over a common surface $S_{1} S_{2}$ . The radius of curvature of the surface $S_{1} S_{2}$ will be

Options:

Answer:

Solution:

Common surface curvature: $\frac{1}{R} = \frac{1}{r _{1}} - \frac{1}{r _{2}}$ .

$R = \frac{r _{1} r _{2}}{r _{2} - r _{1}} = \frac{4 \times 5}{1} = 20 cm$

Answer: B

Stream:JEESubject:PhysicsTopic:FluidSubtopic:Surface Tension

⏱ 3mℹ️ Source: QB

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