A glass capillary sealed at the upper end is of length 0.11 m and internal diameter 2 × 1 0 − 5 m . This tube is immersed vertically into a liquid of surface tension 5.06 × 1 0 − 2 N / m . When the length × 1 0 − 2 m of the tube is immersed in liquid then the liquid level inside and outside the capillary tube becomes the same, then the value of x is : (Assume atmospheric pressure is 1.01 × 1 0 5 m 2 N )

If final pressure of gas in tube is P 2 then P 2 − r 2 T = P 0 (as levels inside and outside are same) i.e. P 2 = P 0 + r 2 T but as temperature remains constant ∴ P 1 V 1 = P 2 V 2 P 0 AL = ( P 0 + r 2 T ) A ( L − h ) On solving, h = 0.01 m

Physics - Fluid Question with Solution | TestHub

PhysicsFluidMedium2 minQB

PhysicsMediuminteger

A glass capillary sealed at the upper end is of length 0.11 m and internal diameter $2 \times 1 0^{- 5} m$ . This tube is immersed vertically into a liquid of surface tension $5.06 \times 1 0^{- 2} N / m$ . When the length $\times 1 0^{- 2} m$ of the tube is immersed in liquid then the liquid level inside and outside the capillary tube becomes the same, then the value of x is : (Assume atmospheric pressure is $1.01 \times 1 0^{5} \frac{N}{m ^{2}}$ )

Answer:

Solution:

If final pressure of gas in tube is $P_{2}$ then $P_{2} - \frac{2 T}{r} = P 0$ (as levels inside and outside are same) i.e. $P_{2} = P_{0} + \frac{2 T}{r}$ but as temperature remains constant $∴ P_{1} V_{1} = P_{2} V_{2}$ $P_{0} AL = (P_{0} + \frac{2 T}{r}) A (L - h)$ On solving, $h = 0.01 m$

Stream:JEESubject:PhysicsTopic:Fluid

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...