Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKTGMedium2 minQB

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One mole of a gas expands with temperature according to the relation $V = k T^{2/3}$ . What is the work done when the temperature changes by 30°C?

Answer:

Solution:

$V = k T^{2/3}$ and $P V = RT$ give $P k = R T^{1/3}$ .

$d V = \frac{2 k}{3} T^{- 1/3} d T, so W = \int P d V = \frac{2 R}{3} \int d T = \frac{2 R}{3} \times 30 = 20 R .$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: QB

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