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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermal ExpansionEasy2 minQB

PhysicsEasysingle choice

A surveyor's $30 m$ steel tape is correct at $6 8^{\circ} F$ . On a hot day the tape has expanded to $30.02 m$ . On that day the tape indicates a distance of $15.02 m$ between two points. The distance between these points is approximately:

Options:

Answer:

Solution:

Every tape division is larger by the factor
$\frac{30.02}{30}$
True distance is
$15.02 \times \frac{30.02}{30} \approx 15.03 m$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

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