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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermodynamicsMedium2 minQB

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The quantity of gas in a closed vessel is halved and the velocities of its molecules are doubled. The final pressure of the gas will be

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Solution:

$v_{r m s} = \frac{3 P}{ρ} = \frac{3 P V}{m} \Rightarrow P = \frac{m v _{r m s}^{2}}{3 V}$ . Halving $m$ and doubling $v_{r m s} : P^{'} = \frac{( m /2 ) ( 2 v _{r m s} ) ^{2}}{3 V} = 2 \times \frac{m v _{r m s}^{2}}{3 V} = 2 P$ .

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics

⏱ 2mℹ️ Source: QB

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