An open insulated calorimeter of water equivalent 20 g is initially at -10°C with 30 g ice. Supply 100°C steam until retained contents first reach 100°C. ci = 0.5 , cw = 1 cal / ( g ∘ C ) , Lf = 80 ,

Question

An open insulated calorimeter of water equivalent 20 g is initially at -10°C with 30 g ice. Supply 100°C steam until retained contents first reach 100°C. ci = 0.5 , cw = 1 cal / ( g ∘ C ) , Lf = 80 , Lv = 540 cal / g . Find minimum steam mass to three decimals, in g.

TestHub · Accepted Answer

Ice warming = 150 cal; melting = 2400; melted-water warming = 3000; calorimeter warming = 2200. Total = 7750 cal . Steam condensing at 10 0 ∘ C supplies 540 cal / g , so mass = 7750/540 = 14.35185 g .

Physics - Heat & Thermo Question with Solution | TestHub

Doubts & Discussion