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What maximum tension the rope $A B$ can withstand if the man of mass of 40 kg can have maximum acceleration of $5 m / s^{2}$ .

Answer:

Solution:

$For max - T = 40 (10 + 5) T = 600 N$

Tension in rope $AB = 2 \times 600 = 1200 N$

Stream:JEESubject:PhysicsTopic:NLM

⏱ 2mℹ️ Source: QB

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