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PhysicsNLMChallenging application of NLMHard2 minQB

PhysicsHardsingle choice

Passage / Comprehension

Two blocks A and B of masses m and 2 m are initially at rest. Length of block B is L and block A is placed at the right end corner of block B and the friction coefficient between them is $μ = 1/2$ . At $t = 0$ a constant force $F = \frac{5 mg}{2}$ begins to act on block B towards right. Just when the block A leaves B, wind begins to blow along y-direction which exerts a constant force $\frac{m g}{2}$ on A. Assume the size of block A is small compared to B and neglect any rotational effects and toppling of block B. (Given $h = 1/2 m, L = 1 m$ and $g = 10 m / s^{2}$ )\\

The magnitude of relative acceleration of A with respect to B (in $m / s^{2}$ ) just after the block A, leaves- B is (Assume wind does not effects motion of B).

Options:

Answer:

Solution:

Just after A leaves: B accelerates at $a_{B} = \frac{5 m g /2}{2 m} = \frac{5 g}{4}$ (friction on B vanishes); A has zero x-acceleration.

A also has wind acceleration $\frac{g}{2}$ along y and gravity $g$ along z.

$a_{re l} = (\frac{5}{4})^{2} + (\frac{1}{2})^{2} + 1^{2} g = \frac{45}{4} g = \frac{3 5}{4} g$ - (D)

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Challenging application of NLM

⏱ 2mℹ️ Source: QB

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