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PhysicsSHMOscillations and SHMMedium2 min

PhysicsMediumsingle choice

A particle of mass 10 g is placed in a potential field $V = (50 x^{2} + 100)$ J/kg. The frequency of oscillation in cycles/s is:

Answer:

Solution:

$V = \frac{1}{2} ω^{2} x^{2} + C$ per kg, with $C$ constant, so $\frac{1}{2} ω^{2} = 50$ , $ω = 10$ rad/s and $f = ω /2 π = 5/ π$ Hz.

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

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