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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKinetic Theory of Gases and Gas LawsEasy2 minQB

PhysicsEasynumerical

Two moles of nitrogen at 300 K are compressed isothermally from 20 L to 5 L. Find the magnitude of the work done on the gas in joules (nearest 10 J). $R = 8.314 J / (mol K)$ .

Answer:

6920.00

Solution:

$W = n RT ln \frac{V _{1}}{V _{2}} = 2 \times 8.314 \times 300 \times ln 4 = 4988.4 \times 1.3863 = 6915$

J, which is 6920 J to the nearest 10 J.

Subject:PhysicsTopic:Heat & ThermoSubtopic:Kinetic Theory of Gases and Gas Laws

⏱ 2mℹ️ Source: QB

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