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PhysicsSHMOscillations and SHMEasy2 min

PhysicsEasyinteger

Find the length of a pendulum with a period of 2 s in $g = π^{2}$ m/s², in m.

Answer:

Solution:

$l = g T^{2} /4 π^{2} = π^{2} \times 4/ (4 π^{2}) = 1$ m.

Subject:PhysicsTopic:SHMSubtopic:Oscillations and SHM

⏱ 2m

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