A constant-volume gas thermometer reads 50 cm and 90 cm Hg at 0 ∘ C and 10 0 ∘ C . When it reads 60 cm Hg, the temperature is:

C = ( P 100 − P 0 ) 100 ( P − P 0 ) . C = ( 90 − 50 ) 100 ( 60 − 50 ) = 2 5 ∘ C .

Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoThermal ExpansionMedium2 minQB

PhysicsMediumsingle choice

A constant-volume gas thermometer reads 50 cm and 90 cm Hg at $0^{\circ} C$ and $10 0^{\circ} C$ . When it reads 60 cm Hg, the temperature is:

Answer:

Solution:

$C = \frac{100 ( P - P _{0} )}{( P _{100} - P _{0} )}$ .

$C = \frac{100 ( 60 - 50 )}{( 90 - 50 )} = 2 5^{\circ} C .$

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

⏱ 2mℹ️ Source: QB

Loading discussions...