A rod has area 2 m m 2 , Y = 100 GPa , α = 2 × 1 0 − 5 per °C. Find tensile force in N giving the elongation of free heating by 25°C.

F = A Y α Δ T = ( 2 × 1 0 − 6 ) ( 1 0 11 ) ( 2 × 1 0 − 5 ) ( 25 ) = 100 N .

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A rod has area $2 m m^{2}, Y = 100 GPa, α = 2 \times 1 0^{- 5}$ per °C. Find tensile force in N giving the elongation of free heating by 25°C.

Answer:

100

Solution:

$F = A Y α Δ T = (2 \times 1 0^{- 6}) (1 0^{11}) (2 \times 1 0^{- 5}) (25) = 100 N$ .

Subject:PhysicsTopic:Heat & ThermoSubtopic:Thermal Expansion

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