Steel rails are laid with length 25 m at 10°C. The highest rail temperature expected is 50°C and α = 1.2 × 1 0 − 5 ∘ C − 1 . The minimum gap to leave between neighbouring rails, in mm, is (nearest int

Question

Steel rails are laid with length 25 m at 10°C. The highest rail temperature expected is 50°C and $α =$ $1.2 \times 1 0^{- 5}^{\circ} C^{- 1}$ . The minimum gap to leave between neighbouring rails, in mm, is (nearest integer):

Answer:

12

Solution:

$Δ L = Lα Δ T = 25 \times 1.2 \times 1 0^{- 5} \times 40 = 1.2 \times 1 0^{- 2} m = 12 mm$ .

TestHub · Accepted Answer

Δ L = Lα Δ T = 25 × 1.2 × 1 0 − 5 × 40 = 1.2 × 1 0 − 2 m = 12 mm .

Physics - Heat & Thermo Question with Solution | TestHub

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