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PhysicsHeat & ThermoThermodynamicsMedium2 minQB

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If one mole of monoatomic gas is mixed with one mole of a diatomic gas, the value of $γ$ for the mixture is

Answer:

Solution:

$C_{V} = \frac{1 \times \frac{3 R}{2} + 1 \times \frac{5 R}{2}}{2} = 2 R; C_{P} = C_{V} + R = 3 R$ .

$γ = \frac{C _{P}}{C _{V}} = \frac{3 R}{2 R} = 1.50.$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Thermodynamics

⏱ 2mℹ️ Source: QB

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