Ther.m.s. velocity of oxygen molecule at 1 6 ∘ C is 474 m / sec . The r.m.s. velocity in m / s of hydrogen molecule at 12 7 ∘ C is

v oxg . = 32 3 R × 289 ( v rms = M 3 RT ) v H = 2 3 R × 400 so v H = 2230.59 m / sec

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PhysicsHeat & ThermoKTGEasy2 minPYQ_2020

PhysicsEasysingle choice

Ther.m.s. velocity of oxygen molecule at $1 6^{\circ} C$ is $474 m / sec$ . The r.m.s. velocity in $m / s$ of hydrogen molecule at $12 7^{\circ} C$ is

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Solution:

$v_{oxg .} = \frac{3 R \times 289}{32} (v_{rms} = \frac{3 RT}{M})$ $v_{H} = \frac{3 R \times 400}{2}$ so $v_{H} = 2230.59 m / sec$

Stream:BITSATSubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: PYQ_2020

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