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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Work kinetic energy theoremEasy2 minQB

PhysicsEasysingle choice

The velocity-time graph of a particle of mass $10 kg$ is shown in the figure. The net work done on the particle in the first two seconds of the motion is

Options:

Answer:

Solution:

$v = - 5 t + 50$

$v_{t = 2} = 40$

$Work done = ∆ K . E . = \frac{1}{2} (40^{2} - 50^{2}) \times 10$

$= - 4500$ J

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Work kinetic energy theorem

⏱ 2mℹ️ Source: QB

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