Start Free Mock LoginAlready registered? Login here

Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Calculation of workMedium2 minQB

PhysicsMediumsingle choice

A particle experiences a variable force $\vec{F} = (4 x \hat{i} + 3 y^{2} \hat{j})$ in a horizontal $x - y$ plane. Assume distance in meters and force is newton. If the particle moves from point $(1, 2)$ to point $(2, 3)$ in the $x - y$ plane, then Kinetic Energy changes by :

Options:

Answer:

Solution:

Using Work energy theorem,

Kinetic energy $∆ K E = W = \int_{1}^{2} 4 x d x + \int_{2}^{3} 3 y^{2} d y$

$= {[\frac{4 x^{2}}{2}]}_{1}^{2} + {[\frac{3 y^{3}}{3}]}_{2}^{3}$

$= [2 \times 2^{2} - 2 \times 1^{2}] + [3^{2} - 2^{3}] = 6 + 19$

$= 25$ Joules

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...