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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Calculation of workEasy2 minQB

PhysicsEasynumerical

A block of mass $10 kg$ is moving along $x$ -axis under the action of force $F = 5 x N$ . The work done by the force in moving the block from $x = 2 m$ to $4 m$ will be _______ $J$ .

Answer:

30.00

Solution:

Work done is $W = \int F d x$
It is given that
$F = 5 x N$
So, work done is
$W = \int_{2}^{4} 5 x d x = {\frac{5 x^{2}}{2}}_{2}^{4} \Rightarrow W = \frac{5 (16 - 4)}{2} = 30 J$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: QB

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