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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Calculation of workEasy2 minQB

PhysicsEasysingle choice

A force $F = α + β x^{2}$ acts on an object in the x -direction. The work done by the force is 5 J when the object is displaced by 1 m . If the constant $α = 1 N$ then $β$ will be

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Solution:

$F = α + β x^{2}$ Work done $\int d w = \int F \cdot d x$ $\Rightarrow Δ W = \int F \cdot d x = \int (α + β x^{2}) d x \Rightarrow Δ W = αx + \frac{β x ^{3}}{3}_{0}^{1} = α + \frac{β}{3} = 5$ Given $α = 1$ So, $\frac{β}{3} = 4$ $\Rightarrow β = 12 N / m^{2}$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: QB

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