A particle gets displaced by Δ r ˉ = ( 2 i ^ + 3 j ^ + 4 k ^ ) m under the action of a force F = ( 7 i ^ + 4 j ^ + 3 k ^ ) . The change in its kinetic energy is

According to work-energy theorem, Change in kinetic energy = work done = F ⋅ Δ r = ( 7 i ^ + 4 j ^ + 3 k ^ ) ⋅ ( 2 i ^ + 3 j ^ + 4 k ^ ) = 14 + 12 + 12 = 38 J

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PhysicsW.E.P.Calculation of workEasy2 minQB

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A particle gets displaced by $Δ \overset{r}{ˉ} = (2 \hat{i} + 3 \hat{j} + 4 \hat{k}) m$ under the action of a force $F = (7 \hat{i} + 4 \hat{j} + 3 \hat{k})$ . The change in its kinetic energy is

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According to work-energy theorem, Change in kinetic energy $=$ work done $= F \cdot Δ r = (7 \hat{i} + 4 \hat{j} + 3 \hat{k}) \cdot (2 \hat{i} + 3 \hat{j} + 4 \hat{k})$ $= 14 + 12 + 12 = 38 J$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: QB

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