Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Work kinetic energy theoremHard2 minQB

PhysicsHardsingle choice

The system shown is released from rest. Speed of block A , after block B has descended by 2 cm , is :-(take $g = 10 m / s^{2}$ )

Answer:

Solution:

$30 \times 0.02 - 0.5 \times 20 \times 0.02 = \frac{1}{2} (2 + 3) V^{2}$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Work kinetic energy theorem

⏱ 2mℹ️ Source: QB

Loading discussions...