A stationary particle breaks into two parts of masses m A and m B which move with velocities v A and v B respectively. The ratio of their kinetic energies ( K B : K A ) is :

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A stationary particle breaks into two parts of masses m A ​ and m B ​ which move with velocities v A ​ and v B ​ respectively. The ratio of their kinetic energies ( K B ​ : K A ​ ) is :

TestHub · Accepted Answer

Initial momentum is zero. ​ Hence ∣ P A ​ ∣ = ∣ P B ​ ∣ ⇒ m A ​ v B ​ = m B ​ v B ​ ( KE ) B ​ ( KE ) A ​ ​ = 2 1 ​ m B ​ v B 2 ​ 2 1 ​ m A ​ v A 2 ​ ​ = v B ​ v A ​ ​ ( KE ) A ​ ( KE ) B ​ ​ = v A ​ v B ​ ​ ​

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