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PhysicsW.E.P.Work kinetic energy theoremMedium2 min

PhysicsMediummultiple choice

Position-time graph of a particle moving in a straight line is as shown in figure. Select the correct alternative(s) :

Answer:

B, C, D

Solution:

Work done by the spring on block = loss in spring P.E. $= \frac{1}{2} k a^{2} - \frac{1}{2} k b^{2} = \frac{1}{2} k (a^{2} - b^{2})$ .

This is also work done against friction $= μ m g (a + b)$ .

$∴ μ = \frac{\frac{1}{2} k ( a ^{2} - b ^{2} )}{m g ( a + b )} = \frac{k}{2 m g} (a - b)$ .

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Work kinetic energy theorem

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